What is the answer to solvefor x,((d^2*y))/((d*x^2))+y=0 ?

The answer to solvefor x,((d^2*y))/((d*x^2))+y=0 is x=isqrt(d),x=-isqrt(d);\quad y\ne 0

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solvefor x,((d^2y))/((dx^2))+y=0

solve for

x, \frac{( d ^{2} \cdot y )}{( d \cdot x ^{2} )} + y = 0

x = i d, x = - i d; y \neq = 0

Solution steps

\frac{( d ^{2} y )}{( d x ^{2} )} + y = 0

Simplify

\frac{d ^{2} y}{d x ^{2}} : \frac{d y}{x ^{2}}

\frac{d y}{x ^{2}} + y = 0

Multiply both sides by

x^{2}

d y + y x^{2} = 0

Solve

d y + y x^{2} = 0 : x = i d, x = - i d; y \neq = 0

x = i d, x = - i d; y \neq = 0

x, g^{- 1} (2) g = \frac{20}{x} + 1

\frac{133}{4 \cdot ( x - \frac{13}{55} ) - 10 x} = 2 x - 1

\frac{( x - 2 )}{( x + 3 )} = 2

\frac{1}{( x ^{2} - 2 x - 8 )} = \frac{a}{( x - 4 )} + \frac{b}{( x + 2 )}

\frac{1}{x ^{2}} = 0

What is the answer to solvefor x,((d^2*y))/((d*x^2))+y=0 ?
The answer to solvefor x,((d^2*y))/((d*x^2))+y=0 is x=isqrt(d),x=-isqrt(d);\quad y\ne 0