What is the answer to 2((x^2+1}{x^2})-3(\frac{x+1)/x)-4=0 ?

The answer to 2((x^2+1}{x^2})-3(\frac{x+1)/x)-4=0 is x=-1,x= 2/5

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2((x^2+1}{x^2})-3(\frac{x+1)/x)-4=0

2 (\frac{x ^{2} + 1}{x ^{2}}) - 3 (\frac{x + 1}{x}) - 4 = 0

x = - 1, x = \frac{2}{5}

Decimal Notation

x = - 1, x = 0.4

Solution steps

2 (\frac{x ^{2} + 1}{x ^{2}}) - 3 (\frac{x + 1}{x}) - 4 = 0

Multiply by LCM

2 (x^{2} + 1) - 3 x (x + 1) - 4 x^{2} = 0

Solve

2 (x^{2} + 1) - 3 x (x + 1) - 4 x^{2} = 0 : x = - 1, x = \frac{2}{5}

x = - 1, x = \frac{2}{5}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 1, x = \frac{2}{5}

∣ - 3 x + 2 ∣ = \frac{1}{2 x + 5}

x, \frac{1}{x} + \frac{1}{y} = \frac{1}{3}

\frac{x}{4 ( x - \frac{6}{2} )} = x \frac{( x - 3 )}{14}

\frac{17 ( 2 - x ) - 5 ( x + 12 )}{1 - 7 x} = 8

\frac{2 + x}{( x + 1 )} = 1 + 3

What is the answer to 2((x^2+1}{x^2})-3(\frac{x+1)/x)-4=0 ?
The answer to 2((x^2+1}{x^2})-3(\frac{x+1)/x)-4=0 is x=-1,x= 2/5
Solve for x: 2((x^2+1}{x^2})-3(\frac{x+1)/x)-4=0
The solution is x=-1,x= 2/5