What is the answer to x^2+x= 2/(x^2+x+1) ?

The answer to x^2+x= 2/(x^2+x+1) is x=(sqrt(5)-1)/2 ,x=-(sqrt(5)+1)/2

Solve for x: x^2+x= 2/(x^2+x+1)

The solution is x=(sqrt(5)-1)/2 ,x=-(sqrt(5)+1)/2

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x^{2} + x = \frac{2}{x ^{2} + x + 1}

x = \frac{5 - 1}{2}, x = - \frac{5 + 1}{2}

Decimal Notation

x = 0.61803 \dots, x = - 1.61803 \dots

Solution steps

x^{2} + x = \frac{2}{x ^{2} + x + 1}

Multiply both sides by

x^{2} + x + 1

x^{2} (x^{2} + x + 1) + x (x^{2} + x + 1) = 2

Solve

x^{2} (x^{2} + x + 1) + x (x^{2} + x + 1) = 2 : x = \frac{5 - 1}{2}, x = - \frac{5 + 1}{2}

x = \frac{5 - 1}{2}, x = - \frac{5 + 1}{2}

\frac{( 1.2 - n )}{( 1 - n )} = 1.4

\frac{( x - 3 )}{x} = \frac{( x + 3 )}{( x + 8 )}

\frac{2 x + 4}{5 x} = 23 x - 6

\frac{( 0.5 ( x ^{5} ) )}{( 5 x ^{3} - 2 x ^{2} + 3 x + 7 )} = 5

k \cdot l = \frac{6}{7 \cdot ( j + 6 k ) e}

What is the answer to x^2+x= 2/(x^2+x+1) ?
The answer to x^2+x= 2/(x^2+x+1) is x=(sqrt(5)-1)/2 ,x=-(sqrt(5)+1)/2
Solve for x: x^2+x= 2/(x^2+x+1)
The solution is x=(sqrt(5)-1)/2 ,x=-(sqrt(5)+1)/2