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((2x^2+9x-5))/((x^4+1))=0437=((x+7))/(2*3(-4+x))1/(2x[ 3/4+x])=-7/10((n-8)!)/((n-9)!)=99/(x^4)+8/(x^2)=1
Frequently Asked Questions (FAQ)
What is the answer to x^{-2}-x^{-1}-6=0 ?
The answer to x^{-2}-x^{-1}-6=0 is x=-1/2 ,x= 1/3Solve for x: x^{-2}-x^{-1}-6=0
The solution is x=-1/2 ,x= 1/3