What is the answer to solvefor x,t= 1/((x-y))*(x+y) ?

The answer to solvefor x,t= 1/((x-y))*(x+y) is x=(y+ty)/(t-1);\quad t\ne 1

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solvefor x,t= 1/((x-y))*(x+y)

solve for

x, t = \frac{1}{( x - y )} \cdot (x + y)

x = \frac{y + t y}{t - 1}; t \neq = 1

Solution steps

t = \frac{1}{( x - y )} (x + y)

Simplify

\frac{1}{x - y} (x + y) : \frac{x + y}{x - y}

t = \frac{x + y}{x - y}

Multiply both sides by

x - y

t (x - y) = x + y

Expand

t (x - y) : x t - t y

x t - t y = x + y

Move

t y

to the right side

x t = x + y + t y

Move

x

to the left side

x t - x = y + t y

Factor

x t - x : x (t - 1)

x (t - 1) = y + t y

Divide both sides by

t - 1; t \neq = 1

x = \frac{y + t y}{t - 1}; t \neq = 1

a, a - c = \frac{( 2 ( a + b ) )}{a}

\frac{( 3 x - 6 )}{4 x} = \frac{5}{8}

\frac{5 x + 7}{2} = \frac{3}{2 x - 14}

3 x^{- 2} = \frac{4}{27}

\frac{1}{4 - 2 - \frac{1}{3} x} = 1 - x

What is the answer to solvefor x,t= 1/((x-y))*(x+y) ?
The answer to solvefor x,t= 1/((x-y))*(x+y) is x=(y+ty)/(t-1);\quad t\ne 1