What is the answer to 1/((x^2+1))+1/((x-1))= 6/5 ?

The answer to 1/((x^2+1))+1/((x-1))= 6/5 is x=2,x=-1/12+i(sqrt(71))/(12),x=-1/12-i(sqrt(71))/(12)

Solve for x: 1/((x^2+1))+1/((x-1))= 6/5

The solution is x=2,x=-1/12+i(sqrt(71))/(12),x=-1/12-i(sqrt(71))/(12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{( x ^{2} + 1 )} + \frac{1}{( x - 1 )} = \frac{6}{5}

x = 2, x = - \frac{1}{12} + i \frac{71}{12}, x = - \frac{1}{12} - i \frac{71}{12}

Solution steps

\frac{1}{( x ^{2} + 1 )} + \frac{1}{( x - 1 )} = \frac{6}{5}

Multiply by LCM

5 (x - 1) + 5 (x^{2} + 1) = 6 (x - 1) (x^{2} + 1)

Solve

5 (x - 1) + 5 (x^{2} + 1) = 6 (x - 1) (x^{2} + 1) : x = 2, x = - \frac{1}{12} + i \frac{71}{12}, x = - \frac{1}{12} - i \frac{71}{12}

x = 2, x = - \frac{1}{12} + i \frac{71}{12}, x = - \frac{1}{12} - i \frac{71}{12}

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = 2, x = - \frac{1}{12} + i \frac{71}{12}, x = - \frac{1}{12} - i \frac{71}{12}

x, \frac{3}{x} + \frac{2}{y} = 0

\frac{3 x}{7 x + 20} = \frac{24}{76}

- x - 2 - 7 x (\frac{1}{x} - \frac{1}{2}) = \frac{( 1 + \frac{x}{2} )}{2} + \frac{11}{2}

\frac{20}{5} = \frac{30}{x}

\frac{( x - 2 )}{x} + \frac{4}{( x - 2 )} = \frac{8}{( x ^{2} - 2 x )}

What is the answer to 1/((x^2+1))+1/((x-1))= 6/5 ?
The answer to 1/((x^2+1))+1/((x-1))= 6/5 is x=2,x=-1/12+i(sqrt(71))/(12),x=-1/12-i(sqrt(71))/(12)
Solve for x: 1/((x^2+1))+1/((x-1))= 6/5
The solution is x=2,x=-1/12+i(sqrt(71))/(12),x=-1/12-i(sqrt(71))/(12)