What is the answer to ((9x+7)}{2-(x-\frac{(x-2))/2)}=36 ?

The answer to ((9x+7)}{2-(x-\frac{(x-2))/2)}=36 is x= 29/27

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((9x+7)}{2-(x-\frac{(x-2))/2)}=36

\frac{( 9 x + 7 )}{2 - ( x - \frac{( x - 2 )}{2} )} = 36

x = \frac{29}{27}

Decimal Notation

x = 1.07407 \dots

Solution steps

\frac{( 9 x + 7 )}{2 - ( x - \frac{( x - 2 )}{2} )} = 36

Simplify

\frac{9 x + 7}{2 - ( x - \frac{x - 2}{2} )} : \frac{2 ( 9 x + 7 )}{- x + 2}

\frac{2 ( 9 x + 7 )}{- x + 2} = 36

Multiply both sides by

- x + 2

2 (9 x + 7) = 36 (- x + 2)

Expand

2 (9 x + 7) : 18 x + 14

Expand

36 (- x + 2) : - 36 x + 72

18 x + 14 = - 36 x + 72

Move

14

to the right side

18 x = - 36 x + 58

Move

36 x

to the left side

54 x = 58

Divide both sides by

54

x = \frac{29}{27}

Verify Solutions

Find undefined (singularity) points:

x = 2

Combine undefined points with solutions:

x = \frac{29}{27}

\frac{x ^{2} + 1}{( x ^{2} ) - 5 ( a + \frac{1}{x} ) + 2} = 0

\frac{\frac{22}{15}}{( \frac{1}{3} - 5 x )} = - \frac{22}{5}

\frac{7}{15 \cdot x + 3} = \frac{3}{5}

x, r + s - 2 t = (2 x + y)^{- 2}

\frac{x ^{1}}{( 243 ) x} = 3^{3}

What is the answer to ((9x+7)}{2-(x-\frac{(x-2))/2)}=36 ?
The answer to ((9x+7)}{2-(x-\frac{(x-2))/2)}=36 is x= 29/27
Solve for x: ((9x+7)}{2-(x-\frac{(x-2))/2)}=36
The solution is x= 29/27