What is the answer to (x^2+2)/(5x)= 2/7 ?

The answer to (x^2+2)/(5x)= 2/7 is x= 5/7+i(sqrt(73))/7 ,x= 5/7-i(sqrt(73))/7

Solve for x: (x^2+2)/(5x)= 2/7

The solution is x= 5/7+i(sqrt(73))/7 ,x= 5/7-i(sqrt(73))/7

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\frac{x ^{2} + 2}{5 x} = \frac{2}{7}

x = \frac{5}{7} + i \frac{73}{7}, x = \frac{5}{7} - i \frac{73}{7}

Solution steps

\frac{x ^{2} + 2}{5 x} = \frac{2}{7}

Cross multiply

(x^{2} + 2) \cdot 7 = 10 x

Solve

(x^{2} + 2) \cdot 7 = 10 x : x = \frac{5}{7} + i \frac{73}{7}, x = \frac{5}{7} - i \frac{73}{7}

x = \frac{5}{7} + i \frac{73}{7}, x = \frac{5}{7} - i \frac{73}{7}

\frac{- 15}{4 - 17 x} = 9 + 10 x

\frac{( x ^{2} + 3 )}{( x - 3 )} - \frac{( x + 6 )}{( 3 - x )} = 1

(x^{4})^{2} = \frac{2 ^{12}}{x ^{5}}

\frac{( x + 1 ) ^{2} + 14}{4 x + 5} = n

\frac{1}{x ^{2}} - \frac{5}{x} + 2 = 0

What is the answer to (x^2+2)/(5x)= 2/7 ?
The answer to (x^2+2)/(5x)= 2/7 is x= 5/7+i(sqrt(73))/7 ,x= 5/7-i(sqrt(73))/7
Solve for x: (x^2+2)/(5x)= 2/7
The solution is x= 5/7+i(sqrt(73))/7 ,x= 5/7-i(sqrt(73))/7