What is the answer to solvefor t,g=2 h/(t^2) ?

The answer to solvefor t,g=2 h/(t^2) is t=sqrt((2h)/g),t=-sqrt((2h)/g);\quad g\ne 0

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solvefor t,g=2 h/(t^2)

solve for

t, g = 2 \frac{h}{t ^{2}}

t = \frac{2 h}{g}, t = - \frac{2 h}{g}; g \neq = 0

Solution steps

g = 2 \cdot \frac{h}{t ^{2}}

Simplify

2 \cdot \frac{h}{t ^{2}} : \frac{2 h}{t ^{2}}

g = \frac{2 h}{t ^{2}}

Multiply both sides by

t^{2}

g t^{2} = 2 h

Solve

g t^{2} = 2 h : t = \frac{2 h}{g}, t = - \frac{2 h}{g}; g \neq = 0

t = \frac{2 h}{g}, t = - \frac{2 h}{g}; g \neq = 0

\frac{3 - 1}{x} = \frac{1}{2}

x^{2} + (\frac{1}{x ^{2}}) = 27

\frac{( 4 x - 1 )}{( 2 x )} = 5

\frac{( x - 1 )}{2 - ( x + 1 ) \cdot 0.3} = 3

\frac{x}{( x ^{2} - 9 )} + \frac{4}{( x + 3 )} = \frac{3}{( x ^{2} - 9 )}

What is the answer to solvefor t,g=2 h/(t^2) ?
The answer to solvefor t,g=2 h/(t^2) is t=sqrt((2h)/g),t=-sqrt((2h)/g);\quad g\ne 0