What is the answer to (z^2-4a^2-2-1)/(z^2)=0 ?

The answer to (z^2-4a^2-2-1)/(z^2)=0 is z=sqrt(4a^2+3),z=-sqrt(4a^2+3)

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(z^2-4a^2-2-1)/(z^2)=0

\frac{z ^{2} - 4 a ^{2} - 2 - 1}{z ^{2}} = 0

z = 4 a^{2} + 3, z = - 4 a^{2} + 3

Solution steps

\frac{z ^{2} - 4 a ^{2} - 2 - 1}{z ^{2}} = 0

Simplify

\frac{z ^{2} - 4 a ^{2} - 2 - 1}{z ^{2}} : \frac{z ^{2} - 4 a ^{2} - 3}{z ^{2}}

\frac{z ^{2} - 4 a ^{2} - 3}{z ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

z^{2} - 4 a^{2} - 3 = 0

Solve

z^{2} - 4 a^{2} - 3 = 0 : z = 4 a^{2} + 3, z = - 4 a^{2} + 3

z = 4 a^{2} + 3, z = - 4 a^{2} + 3

18 t = \frac{0 + 1}{2 ( 3 ) t ^{2}}

\frac{a}{x} = \frac{x}{b + 2}

(\frac{2}{x ^{2}}) - (\frac{5}{x}) + (\frac{2}{1}) = 0

x, \frac{3}{x} - \frac{1}{m} = \frac{2}{m}

\frac{4.5 x - 1}{3 x} = 12

What is the answer to (z^2-4a^2-2-1)/(z^2)=0 ?
The answer to (z^2-4a^2-2-1)/(z^2)=0 is z=sqrt(4a^2+3),z=-sqrt(4a^2+3)