What is the answer to 2((x^2+1}{(x^2)})-3(\frac{x+1)/x)=1 ?

The answer to 2((x^2+1}{(x^2)})-3(\frac{x+1)/x)=1 is x=-2,x= 1/2

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2((x^2+1}{(x^2)})-3(\frac{x+1)/x)=1

2 (\frac{x ^{2} + 1}{( x ^{2} )}) - 3 (\frac{x + 1}{x}) = 1

x = - 2, x = \frac{1}{2}

Decimal Notation

x = - 2, x = 0.5

Solution steps

2 (\frac{x ^{2} + 1}{( x ^{2} )}) - 3 (\frac{x + 1}{x}) = 1

Multiply by LCM

2 (x^{2} + 1) - 3 x (x + 1) = x^{2}

Solve

2 (x^{2} + 1) - 3 x (x + 1) = x^{2} : x = - 2, x = \frac{1}{2}

x = - 2, x = \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 2, x = \frac{1}{2}

\frac{( 0.3 + 0.7 y )}{y} = 0.85

\frac{1}{3} + \frac{a}{x} = - 1

\frac{- 2}{( 9 - x ^{2} )} = 0

\frac{11}{3} = \frac{5}{3 - x}

2 + \frac{2}{p} + \frac{1}{2} p^{2} = \frac{1}{2}

What is the answer to 2((x^2+1}{(x^2)})-3(\frac{x+1)/x)=1 ?
The answer to 2((x^2+1}{(x^2)})-3(\frac{x+1)/x)=1 is x=-2,x= 1/2
Solve for x: 2((x^2+1}{(x^2)})-3(\frac{x+1)/x)=1
The solution is x=-2,x= 1/2