What is the answer to sqrt(x)+sqrt(x-\sqrt{1-x)}=1 ?

The answer to sqrt(x)+sqrt(x-\sqrt{1-x)}=1 is x= 16/25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sqrt(x)+sqrt(x-\sqrt{1-x)}=1

x + x - 1 - x = 1

x = \frac{16}{25}

Decimal Notation

x = 0.64

Solution steps

x + x - 1 - x = 1

Remove square roots

25 x^{2} = 16 x

Solve

25 x^{2} = 16 x : x = 0, x = \frac{16}{25}

x = 0, x = \frac{16}{25}

Verify Solutions:

x = 0

False

, x = \frac{16}{25}

True

The solution is

x = \frac{16}{25}

\frac{( 2 x + 7 )}{( x + 2 )} = 1

2 x - 14 = \frac{288}{( x )}

3 x^{2} - 2 6 x + 2 = 0

x^{\frac{2}{5}} - 3 x^{\frac{1}{5}} + 2 = 0

a, c = a^{2} + b^{2}

What is the answer to sqrt(x)+sqrt(x-\sqrt{1-x)}=1 ?
The answer to sqrt(x)+sqrt(x-\sqrt{1-x)}=1 is x= 16/25
Solve for x: sqrt(x)+sqrt(x-\sqrt{1-x)}=1
The solution is x= 16/25