What is the answer to sqrt(x^2+x+1)=1 ?

The answer to sqrt(x^2+x+1)=1 is x=0,x=-1

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sqrt(x^2+x+1)=1

x^{2} + x + 1 = 1

x = 0, x = - 1

Solution steps

x^{2} + x + 1 = 1

Square both sides:

x^{2} + x + 1 = 1

x^{2} + x + 1 = 1

Solve

x^{2} + x + 1 = 1 : x = 0, x = - 1

x = 0, x = - 1

Verify Solutions:

x = 0

True

, x = - 1

True

The solutions are

x = 0, x = - 1

m = \frac{m ^{0}}{1 - \frac{v ^{2}}{c ^{2}}}

x = \frac{2}{3}

2 + 4 x^{\frac{1}{2}} = 0

2 x + 2 x^{\frac{- 1}{2}} = 5

(1) 9 x^{2} - 25 = 12

What is the answer to sqrt(x^2+x+1)=1 ?
The answer to sqrt(x^2+x+1)=1 is x=0,x=-1
Solve for x: sqrt(x^2+x+1)=1
The solution is x=0,x=-1