What is the answer to sqrt(x^2-x)=sqrt(3-x) ?

The answer to sqrt(x^2-x)=sqrt(3-x) is x=sqrt(3),x=-sqrt(3)

Solve for x: sqrt(x^2-x)=sqrt(3-x)

The solution is x=sqrt(3),x=-sqrt(3)

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Popular >

x^{2} - x = 3 - x

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

x^{2} - x = 3 - x

Square both sides:

x^{2} - x = 3 - x

x^{2} - x = 3 - x

Solve

x^{2} - x = 3 - x : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions:

x = 3

True

, x = - 3

True

The solutions are

x = 3, x = - 3

x + 2 x - 1 = 2

2 x^{2} - 2 6 x + 3 = 0

6 x^{2} + 7 5 x + 10 = 0

x - 3 = 5 - x

x^{\frac{- 3}{4}} = \frac{1}{8}

What is the answer to sqrt(x^2-x)=sqrt(3-x) ?
The answer to sqrt(x^2-x)=sqrt(3-x) is x=sqrt(3),x=-sqrt(3)
Solve for x: sqrt(x^2-x)=sqrt(3-x)
The solution is x=sqrt(3),x=-sqrt(3)