What are the solutions to the equation 4x^2+20x+9=0 ?

The solutions to the equation 4x^2+20x+9=0 are x=-1/2 ,x=-9/2

Find the zeros of 4x^2+20x+9=0

The zeros of 4x^2+20x+9=0 are x=-1/2 ,x=-9/2

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4 x^{2} + 20 x + 9 = 0

x = - \frac{1}{2}, x = - \frac{9}{2}

Solution steps

4 x^{2} + 20 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 9 = 16

x_{1, 2} = \frac{- 20 \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 16}{2 \cdot 4}, x_{2} = \frac{- 20 - 16}{2 \cdot 4}

x = \frac{- 20 + 16}{2 \cdot 4} : - \frac{1}{2}

x = \frac{- 20 - 16}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{9}{2}

2 x^{2} - 5 x = 0

x^{2} + 12 x + 35 \geq 0

x (x + 2) (x - 2) \leq 0

- 3 x^{2} + 18 x - 15 = 0

\frac{1}{25} - 9 z^{2}

What are the solutions to the equation 4x^2+20x+9=0 ?
The solutions to the equation 4x^2+20x+9=0 are x=-1/2 ,x=-9/2
Find the zeros of 4x^2+20x+9=0
The zeros of 4x^2+20x+9=0 are x=-1/2 ,x=-9/2