What is the answer to (x^2-1)*sqrt(2x-1)=0 ?

The answer to (x^2-1)*sqrt(2x-1)=0 is x= 1/2 ,x=1

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(x^2-1)*sqrt(2x-1)=0

(x^{2} - 1) \cdot 2 x - 1 = 0

x = \frac{1}{2}, x = 1

Decimal Notation

x = 0.5, x = 1

Solution steps

(x^{2} - 1) 2 x - 1 = 0

Factor

(x^{2} - 1) 2 x - 1 : 2 x - 1 (x + 1) (x - 1)

2 x - 1 (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 1 = 0 or x - 1 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

x = \frac{1}{2}, x = - 1, x = 1

Verify Solutions:

x = \frac{1}{2}

True

, x = - 1

False

, x = 1

True

The solutions are

x = \frac{1}{2}, x = 1

x, t^{- 1} = \frac{( l \cdot t ^{- 1} )}{x}

\frac{1}{3} \cdot 5 x - \frac{1}{2} = \frac{3}{2} \cdot 5 x - 2 5 x

x + 3 = x + 1

x^{2} + 13 = 8 - x

\frac{8 x ^{2} + 1}{( x )} = \frac{5}{2}

What is the answer to (x^2-1)*sqrt(2x-1)=0 ?
The answer to (x^2-1)*sqrt(2x-1)=0 is x= 1/2 ,x=1
Solve for x: (x^2-1)*sqrt(2x-1)=0
The solution is x= 1/2 ,x=1