What is the answer to sqrt((x-4)^2)+sqrt((1-x)^2)=7 ?

The answer to sqrt((x-4)^2)+sqrt((1-x)^2)=7 is x=-1,x=6

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sqrt((x-4)^2)+sqrt((1-x)^2)=7

(x - 4)^{2} + (1 - x)^{2} = 7

x = - 1, x = 6

Solution steps

(x - 4)^{2} + (1 - x)^{2} = 7

Remove square roots

36 x^{2} + 408 x + 1156 = 196 x^{2} - 392 x + 196

Solve

36 x^{2} + 408 x + 1156 = 196 x^{2} - 392 x + 196 : x = - 1, x = 6

x = - 1, x = 6

Verify Solutions:

x = - 1

True

, x = 6

True

The solutions are

x = - 1, x = 6

10 x + x - 2 = 0

- x^{2} + 25 + x = 1

x = 5

2 2 x + 1 - 2 x = 1

x - 1 = 3

What is the answer to sqrt((x-4)^2)+sqrt((1-x)^2)=7 ?
The answer to sqrt((x-4)^2)+sqrt((1-x)^2)=7 is x=-1,x=6
Solve for x: sqrt((x-4)^2)+sqrt((1-x)^2)=7
The solution is x=-1,x=6