What is the answer to (x^{1/3}+2x^2)/(3-x)=0 ?

The answer to (x^{1/3}+2x^2)/(3-x)=0 is x=0,x=-1/(8^{1/5)}

Solve for x: (x^{1/3}+2x^2)/(3-x)=0

The solution is x=0,x=-1/(8^{1/5)}

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\frac{x ^{\frac{1}{3}} + 2 x ^{2}}{3 - x} = 0

x = 0, x = - \frac{1}{8 ^{\frac{1}{5}}}

Decimal Notation

x = 0, x = - 0.65975 \dots

Solution steps

\frac{x ^{\frac{1}{3}} + 2 x ^{2}}{3 - x} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{\frac{1}{3}} + 2 x^{2} = 0

Remove roots

x = - 8 x^{6}

Solve

x = - 8 x^{6} : x = 0, x = - \frac{1}{8 ^{\frac{1}{5}}}

x = 0, x = - \frac{1}{8 ^{\frac{1}{5}}}

Verify Solutions:

x = 0

True

, x = - \frac{1}{8 ^{\frac{1}{5}}}

True

The solutions are

x = 0, x = - \frac{1}{8 ^{\frac{1}{5}}}

x = x + 6

\frac{( x )}{( 1 - x )} + \frac{( 1 + x )}{( x )} = \frac{5}{2}

x + 10 - x + 19 = - 1

x^{2} - 2 x + 1 - x^{2} - 4 x + 4 = x - 3

x + 7 - 3 x - 2 = 1

What is the answer to (x^{1/3}+2x^2)/(3-x)=0 ?
The answer to (x^{1/3}+2x^2)/(3-x)=0 is x=0,x=-1/(8^{1/5)}
Solve for x: (x^{1/3}+2x^2)/(3-x)=0
The solution is x=0,x=-1/(8^{1/5)}