What is the answer to ((2x+1))/((sqrt(4x^2-5)))=-1 ?

The answer to ((2x+1))/((sqrt(4x^2-5)))=-1 is x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((2x+1))/((sqrt(4x^2-5)))=-1

\frac{( 2 x + 1 )}{( 4 x ^{2} - 5 )} = - 1

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

\frac{( 2 x + 1 )}{( 4 x ^{2} - 5 )} = - 1

Multiply both sides by

4 x^{2} - 5

\frac{2 x + 1}{4 x ^{2} - 5} 4 x^{2} - 5 = - 1 \cdot 4 x^{2} - 5

Simplify

2 x + 1 = - 4 x^{2} - 5

Square both sides:

4 x^{2} + 4 x + 1 = 4 x^{2} - 5

4 x^{2} + 4 x + 1 = 4 x^{2} - 5

Solve

4 x^{2} + 4 x + 1 = 4 x^{2} - 5 : x = - \frac{3}{2}

x = - \frac{3}{2}

Verify Solutions:

x = - \frac{3}{2}

True

The solution is

x = - \frac{3}{2}

2 x - 1 = 3

2 x - 2 = \frac{( x + 7 )}{4}

x, \frac{x}{y} + \frac{y}{x} = \frac{10}{3}

5 x + 1 - 25 = 0

5 x^{2} + 3 x - 33 = 3 x

What is the answer to ((2x+1))/((sqrt(4x^2-5)))=-1 ?
The answer to ((2x+1))/((sqrt(4x^2-5)))=-1 is x=-3/2
Solve for x: ((2x+1))/((sqrt(4x^2-5)))=-1
The solution is x=-3/2