What is the answer to sqrt(2y+\sqrt{2y+4)}=4 ?

The answer to sqrt(2y+\sqrt{2y+4)}=4 is y=6

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sqrt(2y+\sqrt{2y+4)}=4

2 y + 2 y + 4 = 4

y = 6

Solution steps

2 y + 2 y + 4 = 4

Remove square roots

2 y + 4 = 256 - 64 y + 4 y^{2}

Solve

2 y + 4 = 256 - 64 y + 4 y^{2} : y = \frac{21}{2}, y = 6

y = \frac{21}{2}, y = 6

Verify Solutions:

y = \frac{21}{2}

False

, y = 6

True

The solution is

y = 6

x^{2} - 2 3 x - 6 = 0

2 2 x^{2} - 7 x + 10 = x + x^{2} - 12 x + 20

\frac{( 2 x + 7 )}{( x + 2 )} = 1

2 - x = 3 - x

x^{2} + x - 1 + x = 2 x + 3

What is the answer to sqrt(2y+\sqrt{2y+4)}=4 ?
The answer to sqrt(2y+\sqrt{2y+4)}=4 is y=6
Solve for y: sqrt(2y+\sqrt{2y+4)}=4
The solution is y=6