What is the answer to sqrt(x+2x)+sqrt(x+4)=4sqrt(x-1) ?

The answer to sqrt(x+2x)+sqrt(x+4)=4sqrt(x-1) is x=(2(33+2sqrt(66)))/(33)

Solve for x: sqrt(x+2x)+sqrt(x+4)=4sqrt(x-1)

The solution is x=(2(33+2sqrt(66)))/(33)

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x + 2 x + x + 4 = 4 x - 1

x = \frac{2 ( 33 + 2 66 )}{33}

Decimal Notation

x = 2.98473 \dots

Solution steps

x + 2 x + x + 4 = 4 x - 1

Remove square roots

12 x^{2} + 48 x = 144 x^{2} - 480 x + 400

Solve

12 x^{2} + 48 x = 144 x^{2} - 480 x + 400 : x = \frac{2 ( 33 + 2 66 )}{33}, x = \frac{2 ( 33 - 2 66 )}{33}

x = \frac{2 ( 33 + 2 66 )}{33}, x = \frac{2 ( 33 - 2 66 )}{33}

Verify Solutions:

x = \frac{2 ( 33 + 2 66 )}{33}

True

, x = \frac{2 ( 33 - 2 66 )}{33}

False

The solution is

x = \frac{2 ( 33 + 2 66 )}{33}

x, v = d \cdot \frac{( 2 e _{0} )}{x}

x, 3 x + y = a

x = 5

x^{\frac{1}{5}} = 4

\frac{( y + 2 )}{( y - 2 )} = \frac{1}{2}

What is the answer to sqrt(x+2x)+sqrt(x+4)=4sqrt(x-1) ?
The answer to sqrt(x+2x)+sqrt(x+4)=4sqrt(x-1) is x=(2(33+2sqrt(66)))/(33)
Solve for x: sqrt(x+2x)+sqrt(x+4)=4sqrt(x-1)
The solution is x=(2(33+2sqrt(66)))/(33)