What is the answer to solvefor x,z=4+sqrt(x^2+y^2) ?

The answer to solvefor x,z=4+sqrt(x^2+y^2) is x=sqrt(z^2-8z+16-y^2),x=-sqrt(z^2-8z+16-y^2)

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solvefor x,z=4+sqrt(x^2+y^2)

solve for

x, z = 4 + x^{2} + y^{2}

x = z^{2} - 8 z + 16 - y^{2}, x = - z^{2} - 8 z + 16 - y^{2}

Solution steps

z = 4 + x^{2} + y^{2}

Switch sides

4 + x^{2} + y^{2} = z

Move

4

to the right side

x^{2} + y^{2} = z - 4

Square both sides:

x^{2} + y^{2} = z^{2} - 8 z + 16

x^{2} + y^{2} = z^{2} - 8 z + 16

Solve

x^{2} + y^{2} = z^{2} - 8 z + 16 : x = z^{2} - 8 z + 16 - y^{2}, x = - z^{2} - 8 z + 16 - y^{2}

x = z^{2} - 8 z + 16 - y^{2}, x = - z^{2} - 8 z + 16 - y^{2}

5 x^{2} + 2 2 x + 6 = 0

x - 4 + 1 - x = 5

\frac{( 4 + 2 )}{( 2 + 2 )} = n - b

\frac{10 - 12}{( x )} = 8

y^{\frac{1}{3}} - 55 + 376 = (18)^{2}

What is the answer to solvefor x,z=4+sqrt(x^2+y^2) ?
The answer to solvefor x,z=4+sqrt(x^2+y^2) is x=sqrt(z^2-8z+16-y^2),x=-sqrt(z^2-8z+16-y^2)