What is the answer to sqrt(x)+sqrt(1-x)=1 ?

The answer to sqrt(x)+sqrt(1-x)=1 is x=1,x=0

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sqrt(x)+sqrt(1-x)=1

x + 1 - x = 1

x = 1, x = 0

Solution steps

x + 1 - x = 1

Remove square roots

4 x^{2} - 8 x + 4 = 4 - 4 x

Solve

4 x^{2} - 8 x + 4 = 4 - 4 x : x = 1, x = 0

x = 1, x = 0

Verify Solutions:

x = 1

True

, x = 0

True

The solutions are

x = 1, x = 0

\frac{x ^{2}}{3 x ^{\frac{1}{3}} - 2} = 0

x^{0.15} + x = 28

(23 + 10 + x)^{\frac{1}{2}} = 27

\frac{( x - 4 )}{( x + 2 )} = x - 8

5 x^{2} - 6 x + 8 - 5 x^{2} - 6 x - 7 = 1

What is the answer to sqrt(x)+sqrt(1-x)=1 ?
The answer to sqrt(x)+sqrt(1-x)=1 is x=1,x=0
Solve for x: sqrt(x)+sqrt(1-x)=1
The solution is x=1,x=0