What is the answer to solvefor x,3sqrt(2x)-sqrt(5y)=16 ?

The answer to solvefor x,3sqrt(2x)-sqrt(5y)=16 is x=(256+32sqrt(5)sqrt(y)+5y)/(18) {y>= 0}

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solvefor x,3sqrt(2x)-sqrt(5y)=16

solve for

x, 3 2 x - 5 y = 16

x = \frac{256 + 32 5 y + 5 y}{18} {y \geq 0}

Solution steps

3 2 x - 5 y = 16

Expand

3 2 x - 5 y : 3 2 x - 5 y

3 2 x - 5 y = 16

Move

5 y

to the right side

3 2 x = 16 + 5 y

Divide both sides by

3

2 x = \frac{16 + 5 y}{3}

Square both sides:

2 x = \frac{256}{9} + \frac{32 5 y}{9} + \frac{5 y}{9}

2 x = \frac{256}{9} + \frac{32 5 y}{9} + \frac{5 y}{9}

Solve

2 x = \frac{256}{9} + \frac{32 5 y}{9} + \frac{5 y}{9} : x = \frac{256 + 32 5 y + 5 y}{18}

x = \frac{256 + 32 5 y + 5 y}{18}

Verify Solutions:

x = \frac{256 + 32 5 y + 5 y}{18} {y \geq 0}

The solution is

x = \frac{256 + 32 5 y + 5 y}{18} {y \geq 0}

\frac{( x - 1 )}{( x + 1 )} = 1

x + 1 = x - 1

(x + 1 + 1) (5 - x) = 2 x

x, x \cdot y^{2} = x^{\frac{1}{2}} \cdot y

\frac{b - 6}{7} = \frac{- 6}{7 + 5}

What is the answer to solvefor x,3sqrt(2x)-sqrt(5y)=16 ?
The answer to solvefor x,3sqrt(2x)-sqrt(5y)=16 is x=(256+32sqrt(5)sqrt(y)+5y)/(18) {y>= 0}