What is ((2x^2)/(3x^3y^2))^3 ?

The solution to ((2x^2)/(3x^3y^2))^3 is 8/(27x^3y^6)

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simplify ((2x^2)/(3x^3y^2))^3

simplify

(\frac{2 x ^{2}}{3 x ^{3} y ^{2}})^{3}

\frac{8}{27 x ^{3} y ^{6}}

Solution steps

(\frac{2 x ^{2}}{3 x ^{3} y ^{2}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 x ^{2} ) ^{3}}{( 3 x ^{3} y ^{2} ) ^{3}}

Simplify

(2 x^{2})^{3} : 8 x^{6}

= \frac{8 x ^{6}}{( 3 x ^{3} y ^{2} ) ^{3}}

Simplify

(3 x^{3} y^{2})^{3} : 27 x^{9} y^{6}

= \frac{8 x ^{6}}{27 x ^{9} y ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{x ^{6}}{x ^{9}} = \frac{1}{x ^{9 - 6}}

= \frac{8}{27 y ^{6} x ^{9 - 6}}

Subtract the numbers:

9 - 6 = 3

= \frac{8}{27 x ^{3} y ^{6}}

51 2^{- \frac{1}{3}}

- a^{2} - a + 2 = 0

\frac{z}{5} = \frac{3}{10} z + 7

t^{2} - 6 < - t + 14

- u + 15 \geq 9 (- u - 7) - 2

What is ((2x^2)/(3x^3y^2))^3 ?
The solution to ((2x^2)/(3x^3y^2))^3 is 8/(27x^3y^6)