What is the answer to 2x^2+sqrt(x^2+2x+1)=0 ?

The answer to 2x^2+sqrt(x^2+2x+1)=0 is No Solution for x\in\mathbb{R}

Solve for x: 2x^2+sqrt(x^2+2x+1)=0

The solution is No Solution for x\in\mathbb{R}

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2 x^{2} + x^{2} + 2 x + 1 = 0

No Solution for x \in R

Solution steps

2 x^{2} + x^{2} + 2 x + 1 = 0

Remove square roots

x^{2} + 2 x + 1 = 4 x^{4}

Solve

x^{2} + 2 x + 1 = 4 x^{4} : x = - \frac{1}{2}, x = 1

x = - \frac{1}{2}, x = 1

Verify Solutions:

x = - \frac{1}{2}

False

, x = 1

False

The solution is

No Solution for x \in R

x^{2} = x

5 - 2 x - 2 - x = 1

4 a^{0.75} = 0

25 x - 42 + 36 x = 15

2 2 x = 42 x - 1

What is the answer to 2x^2+sqrt(x^2+2x+1)=0 ?
The answer to 2x^2+sqrt(x^2+2x+1)=0 is No Solution for x\in\mathbb{R}
Solve for x: 2x^2+sqrt(x^2+2x+1)=0
The solution is No Solution for x\in\mathbb{R}