What is the answer to solvefor t,89f=sqrt(((1-2t))/((1+2t))) ?

The answer to solvefor t,89f=sqrt(((1-2t))/((1+2t))) is t=(1-7921f^2)/(2(1+7921f^2)) {f>= 0}

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solvefor t,89f=sqrt(((1-2t))/((1+2t)))

solve for

t, 89 f = \frac{( 1 - 2 t )}{( 1 + 2 t )}

t = \frac{1 - 7921 f ^{2}}{2 ( 1 + 7921 f ^{2} )} {f \geq 0}

Solution steps

89 f = \frac{( 1 - 2 t )}{( 1 + 2 t )}

Square both sides:

7921 f^{2} = \frac{1 - 2 t}{1 + 2 t}

7921 f^{2} = \frac{1 - 2 t}{1 + 2 t}

Solve

7921 f^{2} = \frac{1 - 2 t}{1 + 2 t} : t = \frac{1 - 7921 f ^{2}}{2 ( 1 + 7921 f ^{2} )}

t = \frac{1 - 7921 f ^{2}}{2 ( 1 + 7921 f ^{2} )}

Verify Solutions:

t = \frac{1 - 7921 f ^{2}}{2 ( 1 + 7921 f ^{2} )} {f \geq 0}

The solution is

t = \frac{1 - 7921 f ^{2}}{2 ( 1 + 7921 f ^{2} )} {f \geq 0}

x^{2} + 3 3 x - 30 = 0

x x + x - x = 2 x

b = - x - 4 x

(x + 28)^{\frac{1}{3}} - (x - 28)^{\frac{1}{3}} = 2

x^{2} = 3

What is the answer to solvefor t,89f=sqrt(((1-2t))/((1+2t))) ?
The answer to solvefor t,89f=sqrt(((1-2t))/((1+2t))) is t=(1-7921f^2)/(2(1+7921f^2)) {f>= 0}