What is the answer to solvefor x,x^{2/3}+y^{2/3}=a^{2/3} ?

The answer to solvefor x,x^{2/3}+y^{2/3}=a^{2/3} is

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solvefor x,x^{2/3}+y^{2/3}=a^{2/3}

solve for

x, x^{\frac{2}{3}} + y^{\frac{2}{3}} = a^{\frac{2}{3}}

x = a^{2} - 3 a^{\frac{4}{3}} y^{\frac{2}{3}} + 3 a^{\frac{2}{3}} y^{\frac{4}{3}} - y^{2}, x = - a^{2} - 3 a^{\frac{4}{3}} y^{\frac{2}{3}} + 3 a^{\frac{2}{3}} y^{\frac{4}{3}} - y^{2}

Solution steps

x^{\frac{2}{3}} + y^{\frac{2}{3}} = a^{\frac{2}{3}}

Move

y^{\frac{2}{3}}

to the right side

x^{\frac{2}{3}} = a^{\frac{2}{3}} - y^{\frac{2}{3}}

Take both sides of the equation to the power of

3 : x^{2} = a^{2} - 3 a^{\frac{4}{3}} y^{\frac{2}{3}} + 3 a^{\frac{2}{3}} y^{\frac{4}{3}} - y^{2}

x^{2} = a^{2} - 3 a^{\frac{4}{3}} y^{\frac{2}{3}} + 3 a^{\frac{2}{3}} y^{\frac{4}{3}} - y^{2}

Solve

x^{2} = a^{2} - 3 a^{\frac{4}{3}} y^{\frac{2}{3}} + 3 a^{\frac{2}{3}} y^{\frac{4}{3}} - y^{2} : x = a^{2} - 3 a^{\frac{4}{3}} y^{\frac{2}{3}} + 3 a^{\frac{2}{3}} y^{\frac{4}{3}} - y^{2}, x = - a^{2} - 3 a^{\frac{4}{3}} y^{\frac{2}{3}} + 3 a^{\frac{2}{3}} y^{\frac{4}{3}} - y^{2}

x = a^{2} - 3 a^{\frac{4}{3}} y^{\frac{2}{3}} + 3 a^{\frac{2}{3}} y^{\frac{4}{3}} - y^{2}, x = - a^{2} - 3 a^{\frac{4}{3}} y^{\frac{2}{3}} + 3 a^{\frac{2}{3}} y^{\frac{4}{3}} - y^{2}

x + 2 = 2 x + 1

x - 1 - 2 x + 1 = 0

(x - 2)^{\frac{2}{3}} + (x - 2)^{\frac{1}{3}} - 2 = 0

3 x - 27 = 0

x^{\frac{3}{2}} + (x^{2})^{- 2} + x^{3} = 4

What is the answer to solvefor x,x^{2/3}+y^{2/3}=a^{2/3} ?
The answer to solvefor x,x^{2/3}+y^{2/3}=a^{2/3} is