What is the answer to sqrt(4x^2)=x+1 ?

The answer to sqrt(4x^2)=x+1 is x=-1/3 ,x=1

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sqrt(4x^2)=x+1

4 x^{2} = x + 1

x = - \frac{1}{3}, x = 1

Decimal Notation

x = - 0.33333 \dots, x = 1

Solution steps

4 x^{2} = x + 1

Square both sides:

4 x^{2} = x^{2} + 2 x + 1

4 x^{2} = x^{2} + 2 x + 1

Solve

4 x^{2} = x^{2} + 2 x + 1 : x = - \frac{1}{3}, x = 1

x = - \frac{1}{3}, x = 1

Verify Solutions:

x = - \frac{1}{3}

True

, x = 1

True

The solutions are

x = - \frac{1}{3}, x = 1

x + 1 = 9 x - 2

x - 3 = 4

x + 5 - x - 3 = 2

\frac{10 x - 20}{x ^{(\frac{1}{3})}} = 0

m, (m - x) x^{2} - 2 m = 2 - x

What is the answer to sqrt(4x^2)=x+1 ?
The answer to sqrt(4x^2)=x+1 is x=-1/3 ,x=1
Solve for x: sqrt(4x^2)=x+1
The solution is x=-1/3 ,x=1