What is the answer to sqrt(9x^2-6x+1)=x+2 ?

The answer to sqrt(9x^2-6x+1)=x+2 is x= 3/2 ,x=-1/4

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sqrt(9x^2-6x+1)=x+2

9 x^{2} - 6 x + 1 = x + 2

x = \frac{3}{2}, x = - \frac{1}{4}

Decimal Notation

x = 1.5, x = - 0.25

Solution steps

9 x^{2} - 6 x + 1 = x + 2

Square both sides:

9 x^{2} - 6 x + 1 = x^{2} + 4 x + 4

9 x^{2} - 6 x + 1 = x^{2} + 4 x + 4

Solve

9 x^{2} - 6 x + 1 = x^{2} + 4 x + 4 : x = \frac{3}{2}, x = - \frac{1}{4}

x = \frac{3}{2}, x = - \frac{1}{4}

Verify Solutions:

x = \frac{3}{2}

True

, x = - \frac{1}{4}

True

The solutions are

x = \frac{3}{2}, x = - \frac{1}{4}

5 x^{2} + 8 x + 10 = x^{4} + 4

[1.38 (8 + x)^{\frac{1}{2}}] - 1 = 0

2 + 4 x = - 1

\frac{400}{800} = \frac{80}{t _{2}}

1 + x \cdot 2 x^{2} + 8 = x + 1

What is the answer to sqrt(9x^2-6x+1)=x+2 ?
The answer to sqrt(9x^2-6x+1)=x+2 is x= 3/2 ,x=-1/4
Solve for x: sqrt(9x^2-6x+1)=x+2
The solution is x= 3/2 ,x=-1/4