What are the solutions to the equation (x-4)^2=28 ?

The solutions to the equation (x-4)^2=28 are x=2sqrt(7)+4,x=-2sqrt(7)+4

Find the zeros of (x-4)^2=28

The zeros of (x-4)^2=28 are x=2sqrt(7)+4,x=-2sqrt(7)+4

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(x - 4)^{2} = 28

x = 27 + 4, x = - 27 + 4

Solution steps

(x - 4)^{2} = 28

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 28 : x = 27 + 4

Solve

x - 4 = - 28 : x = - 27 + 4

The solutions to the quadratic equation are:

x = 27 + 4, x = - 27 + 4

9 \cdot 13

- 3 x + 3 = 6

5 ∣ 2 x - 3 ∣ - 1 > 9

5 x y - x^{2} t + 2 x y + 3 x^{2} t

- \frac{1.2 ( 10 )}{( 0.01 ( 10 ) ^{2} + 1 ) ^{2}}

What are the solutions to the equation (x-4)^2=28 ?
The solutions to the equation (x-4)^2=28 are x=2sqrt(7)+4,x=-2sqrt(7)+4
Find the zeros of (x-4)^2=28
The zeros of (x-4)^2=28 are x=2sqrt(7)+4,x=-2sqrt(7)+4