What is the answer to sqrt(2x^2+6x+1)=5 ?

The answer to sqrt(2x^2+6x+1)=5 is x=(-3+sqrt(57))/2 ,x=-(3+sqrt(57))/2

Solve for x: sqrt(2x^2+6x+1)=5

The solution is x=(-3+sqrt(57))/2 ,x=-(3+sqrt(57))/2

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2 x^{2} + 6 x + 1 = 5

x = \frac{- 3 + 57}{2}, x = - \frac{3 + 57}{2}

Decimal Notation

x = 2.27491 \dots, x = - 5.27491 \dots

Solution steps

2 x^{2} + 6 x + 1 = 5

Square both sides:

2 x^{2} + 6 x + 1 = 25

2 x^{2} + 6 x + 1 = 25

Solve

2 x^{2} + 6 x + 1 = 25 : x = \frac{- 3 + 57}{2}, x = - \frac{3 + 57}{2}

x = \frac{- 3 + 57}{2}, x = - \frac{3 + 57}{2}

Verify Solutions:

x = \frac{- 3 + 57}{2}

True

, x = - \frac{3 + 57}{2}

True

The solutions are

x = \frac{- 3 + 57}{2}, x = - \frac{3 + 57}{2}

2 x - x^{2} = 1

x^{2} + 5 x = 0

x + x + 24 = 12

x - 2 = x

3 = \frac{81}{( x )}

What is the answer to sqrt(2x^2+6x+1)=5 ?
The answer to sqrt(2x^2+6x+1)=5 is x=(-3+sqrt(57))/2 ,x=-(3+sqrt(57))/2
Solve for x: sqrt(2x^2+6x+1)=5
The solution is x=(-3+sqrt(57))/2 ,x=-(3+sqrt(57))/2