What is the answer to solvefor x,x+sqrt(xy)+y=1 ?

The answer to solvefor x,x+sqrt(xy)+y=1 is x=(-y+2+sqrt(-3y^2+4y))/2 ,x=(-y+2-sqrt(-3y^2+4y))/2

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solvefor x,x+sqrt(xy)+y=1

solve for

x, x + x y + y = 1

x = \frac{- y + 2 + - 3 y ^{2} + 4 y}{2}, x = \frac{- y + 2 - - 3 y ^{2} + 4 y}{2}

Solution steps

x + x y + y = 1

Remove square roots

x y = 2 x y - 2 y + y^{2} - 2 x + x^{2} + 1

Solve

x y = 2 x y - 2 y + y^{2} - 2 x + x^{2} + 1 : x = \frac{- y + 2 + - 3 y ^{2} + 4 y}{2}, x = \frac{- y + 2 - - 3 y ^{2} + 4 y}{2}

x = \frac{- y + 2 + - 3 y ^{2} + 4 y}{2}, x = \frac{- y + 2 - - 3 y ^{2} + 4 y}{2}

Verify Solutions:

x = \frac{- y + 2 + - 3 y ^{2} + 4 y}{2}

True

, x = \frac{- y + 2 - - 3 y ^{2} + 4 y}{2}

True

The solutions are

x = \frac{- y + 2 + - 3 y ^{2} + 4 y}{2}, x = \frac{- y + 2 - - 3 y ^{2} + 4 y}{2}

x = 2022 + 2022 + x

7606 = 552 0^{2} + q^{2}

y, x = y^{\frac{1}{2}}

x^{2} + 3 x + 13 = x - 1

- 6^{2} + 0^{2} = x^{2}

What is the answer to solvefor x,x+sqrt(xy)+y=1 ?
The answer to solvefor x,x+sqrt(xy)+y=1 is x=(-y+2+sqrt(-3y^2+4y))/2 ,x=(-y+2-sqrt(-3y^2+4y))/2