What is the answer to x-(4-x^2)^{0.5}=0 ?

The answer to x-(4-x^2)^{0.5}=0 is x=sqrt(2)

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x-(4-x^2)^{0.5}=0

x - (4 - x^{2})^{0.5} = 0

x = 2

Decimal Notation

x = 1.41421 \dots

Solution steps

x - (4 - x^{2})^{0.5} = 0

Remove square roots

4 - x^{2} = x^{2}

Solve

4 - x^{2} = x^{2} : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

False

The solution is

x = 2

92 x^{2} + 7 x - 7 = 0

6 + 2 x + 4 = 14

7 x^{2} - 3 x = 4 x^{2} - 12 x - 3

x, 19 u = \frac{( 5 x + 1 )}{( 2 x )}

\frac{( x + \frac{1}{x} ) ^{\frac{1}{2}} + ( x + \frac{1}{x} ) 1}{2} = x

What is the answer to x-(4-x^2)^{0.5}=0 ?
The answer to x-(4-x^2)^{0.5}=0 is x=sqrt(2)
Solve for x: x-(4-x^2)^{0.5}=0
The solution is x=sqrt(2)