What is the answer to solvefor x,(b)y=(x+1)^{1/2} ?

The answer to solvefor x,(b)y=(x+1)^{1/2} is x=b^2y^2-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,(b)y=(x+1)^{1/2}

solve for

x, (b) y = (x + 1)^{\frac{1}{2}}

x = b^{2} y^{2} - 1

Solution steps

(b) y = (x + 1)^{\frac{1}{2}}

Square both sides:

b^{2} y^{2} = x + 1

b^{2} y^{2} = x + 1

Solve

b^{2} y^{2} = x + 1 : x = b^{2} y^{2} - 1

x = b^{2} y^{2} - 1

n, y = (5 - n - 7)

13 - x 10 = 8 + 5

x - 13 + 18 - x = x

6 - 2 x + 3 = 5 x

\frac{3 x}{2} = \frac{3}{2}

What is the answer to solvefor x,(b)y=(x+1)^{1/2} ?
The answer to solvefor x,(b)y=(x+1)^{1/2} is x=b^2y^2-1