What is the answer to x^2+4sqrt(x^2)-21=0 ?

The answer to x^2+4sqrt(x^2)-21=0 is x=3,x=-3

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x^2+4sqrt(x^2)-21=0

x^{2} + 4 x^{2} - 21 = 0

x = 3, x = - 3

Solution steps

x^{2} + 4 x^{2} - 21 = 0

Remove square roots

16 x^{2} = x^{4} - 42 x^{2} + 441

Solve

16 x^{2} = x^{4} - 42 x^{2} + 441 : x = 7, x = - 7, x = 3, x = - 3

x = 7, x = - 7, x = 3, x = - 3

Verify Solutions:

x = 7

False

, x = - 7

False

, x = 3

True

, x = - 3

True

The solutions are

x = 3, x = - 3

3 x + 1 - 2 x - 1 = 1

8 x - 12 + 18 x - 27 - 32 x - 48 = 7

23 - 4 + 8 x = 0

a, \frac{( a ^{2} )}{( b ^{2} )} = \frac{a}{b}

x^{\frac{1}{12}} = 4 9^{\frac{1}{24}}

What is the answer to x^2+4sqrt(x^2)-21=0 ?
The answer to x^2+4sqrt(x^2)-21=0 is x=3,x=-3
Solve for x: x^2+4sqrt(x^2)-21=0
The solution is x=3,x=-3