What are the solutions to the equation 5n^2+9n-69=11 ?

The solutions to the equation 5n^2+9n-69=11 are n= 16/5 ,n=-5

Find the zeros of 5n^2+9n-69=11

The zeros of 5n^2+9n-69=11 are n= 16/5 ,n=-5

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5 n^{2} + 9 n - 69 = 11

n = \frac{16}{5}, n = - 5

Solution steps

5 n^{2} + 9 n - 69 = 11

Move

11

to the left side

5 n^{2} + 9 n - 80 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 80 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 80) = 41

n_{1, 2} = \frac{- 9 \pm 41}{2 \cdot 5}

Separate the solutions

n_{1} = \frac{- 9 + 41}{2 \cdot 5}, n_{2} = \frac{- 9 - 41}{2 \cdot 5}

n = \frac{- 9 + 41}{2 \cdot 5} : \frac{16}{5}

n = \frac{- 9 - 41}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

n = \frac{16}{5}, n = - 5

\frac{2 x}{4} = \frac{1 + x}{6}

5 p^{2} + 13 p - 6

\frac{5 - ( - 6 )}{- 4 - ( - 9 )}

\frac{2}{5} + \frac{3}{7}

81 x^{3} y - 12 x^{2} y

What are the solutions to the equation 5n^2+9n-69=11 ?
The solutions to the equation 5n^2+9n-69=11 are n= 16/5 ,n=-5
Find the zeros of 5n^2+9n-69=11
The zeros of 5n^2+9n-69=11 are n= 16/5 ,n=-5