What is the answer to solvefor d,b=r-sqrt(r^2-d^2) ?

The answer to solvefor d,b=r-sqrt(r^2-d^2) is d=sqrt(2br-b^2),d=-sqrt(2br-b^2)

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solvefor d,b=r-sqrt(r^2-d^2)

solve for

d, b = r - r^{2} - d^{2}

d = 2 b r - b^{2}, d = - 2 b r - b^{2}

Solution steps

b = r - r^{2} - d^{2}

Move

r^{2} - d^{2}

to the left side

b + r^{2} - d^{2} = r

Move

b

to the right side

r^{2} - d^{2} = r - b

Square both sides:

r^{2} - d^{2} = r^{2} - 2 b r + b^{2}

r^{2} - d^{2} = r^{2} - 2 b r + b^{2}

Solve

r^{2} - d^{2} = r^{2} - 2 b r + b^{2} : d = 2 b r - b^{2}, d = - 2 b r - b^{2}

d = 2 b r - b^{2}, d = - 2 b r - b^{2}

[1.38 (64 + x^{2})^{\frac{1}{2}}] - 1 = 0

4 + 2 x - 4 = x

x + 7 x + 52 = 0

484 \cdot \frac{25}{x} = 22

x^{2} - 4 x + 5 + 2 x = 0

What is the answer to solvefor d,b=r-sqrt(r^2-d^2) ?
The answer to solvefor d,b=r-sqrt(r^2-d^2) is d=sqrt(2br-b^2),d=-sqrt(2br-b^2)