What is the answer to sqrt(x^2)+sqrt((x-1)^2)=1 ?

The answer to sqrt(x^2)+sqrt((x-1)^2)=1 is 0<= x<= 1

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sqrt(x^2)+sqrt((x-1)^2)=1

x^{2} + (x - 1)^{2} = 1

0 \leq x \leq 1

Solution steps

x^{2} + (x - 1)^{2} = 1

Remove square roots

4 x^{2} - 8 x + 4 = 4 x^{2} - 8 x + 4

Both sides are equal

True for all x

Verify Solutions:

x < 0

False

, x = 0

True

, 0 < x < 1

True

, x = 1

True

, x > 1

False

The solution is

0 \leq x \leq 1

(2 x + 5)^{\frac{1}{3}} = 5

(x^{0.16}) + 80 = 122

y - 19 = 2

x + 7 + x + 2 = \frac{15}{( x + 7 )}

3 x^{2} + 7 5 x + 2 = 0

What is the answer to sqrt(x^2)+sqrt((x-1)^2)=1 ?
The answer to sqrt(x^2)+sqrt((x-1)^2)=1 is 0<= x<= 1
Solve for x: sqrt(x^2)+sqrt((x-1)^2)=1
The solution is 0<= x<= 1