What are the solutions to the equation y^2+6y+9+y^2-9=0 ?

The solutions to the equation y^2+6y+9+y^2-9=0 are y=0,y=-3

Find the zeros of y^2+6y+9+y^2-9=0

The zeros of y^2+6y+9+y^2-9=0 are y=0,y=-3

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y^{2} + 6 y + 9 + y^{2} - 9 = 0

y = 0, y = - 3

Solution steps

y^{2} + 6 y + 9 + y^{2} - 9 = 0

Refine

2 y^{2} + 6 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

6^{2} - 4 \cdot 2 \cdot 0 = 6

y_{1, 2} = \frac{- 6 \pm 6}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- 6 + 6}{2 \cdot 2}, y_{2} = \frac{- 6 - 6}{2 \cdot 2}

y = \frac{- 6 + 6}{2 \cdot 2} : 0

y = \frac{- 6 - 6}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

y = 0, y = - 3

- \frac{5}{4} x^{2} + 30 x - 100 = 0

35 - 4 x > 2

7 - x^{2} = 2 + \frac{x}{2}

x^{3} + 7 x^{2} + 15 x + 9

- 6 x^{2} + 24 x = 0

What are the solutions to the equation y^2+6y+9+y^2-9=0 ?
The solutions to the equation y^2+6y+9+y^2-9=0 are y=0,y=-3
Find the zeros of y^2+6y+9+y^2-9=0
The zeros of y^2+6y+9+y^2-9=0 are y=0,y=-3