What is the answer to 2x^2+2sqrt(5x)-5=0 ?

The answer to 2x^2+2sqrt(5x)-5=0 is x\approx 0.75036…

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2x^2+2sqrt(5x)-5=0

2 x^{2} + 2 5 x - 5 = 0

x \approx 0.75036 \dots

Solution steps

2 x^{2} + 2 5 x - 5 = 0

Remove square roots

20 x = 4 x^{4} - 20 x^{2} + 25

Solve

20 x = 4 x^{4} - 20 x^{2} + 25 : x \approx 0.75036 \dots, x \approx 2.44940 \dots

x \approx 0.75036 \dots, x \approx 2.44940 \dots

Verify Solutions:

x \approx 0.75036 \dots

True

, x \approx 2.44940 \dots

False

The solution is

x \approx 0.75036 \dots

(\frac{x - 1}{x})^{\frac{1}{2}} + (\frac{1 - 1}{x})^{\frac{1}{2}} = x

x + 1 + 2 x + 3 = 5

2 x - 3 = - 1

x, (a) f = - 6 - 3 x

4 x + 9 = 5

What is the answer to 2x^2+2sqrt(5x)-5=0 ?
The answer to 2x^2+2sqrt(5x)-5=0 is x\approx 0.75036…
Solve for x: 2x^2+2sqrt(5x)-5=0
The solution is x\approx 0.75036…