What is the answer to 2x^{-1}+x^{(-1)/2}=6 ?

The answer to 2x^{-1}+x^{(-1)/2}=6 is x= 4/9

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2x^{-1}+x^{(-1)/2}=6

2 x^{- 1} + x^{\frac{- 1}{2}} = 6

x = \frac{4}{9}

Solution steps

2 x^{- 1} + x^{\frac{- 1}{2}} = 6

Expand

2 x^{- 1} + x^{\frac{- 1}{2}} : \frac{2}{x} + \frac{1}{x ^{\frac{1}{2}}}

\frac{2}{x} + \frac{1}{x ^{\frac{1}{2}}} = 6

Remove square roots

\frac{1}{x} = 36 - \frac{24}{x} + \frac{4}{x ^{2}}

Solve

\frac{1}{x} = 36 - \frac{24}{x} + \frac{4}{x ^{2}} : x = \frac{4}{9}, x = \frac{1}{4}

x = \frac{4}{9}, x = \frac{1}{4}

Verify Solutions:

x = \frac{4}{9}

True

, x = \frac{1}{4}

False

The solution is

x = \frac{4}{9}

(x - 1)^{\frac{3}{4}} = 64

3 x^{2} - 4 3 x + 4 = 0

a - 3 a - 18 = 0

x - 5 = - 7 x + 65

d, 2 f = \frac{( d - 7 e )}{( 3 e )}

What is the answer to 2x^{-1}+x^{(-1)/2}=6 ?
The answer to 2x^{-1}+x^{(-1)/2}=6 is x= 4/9
Solve for x: 2x^{-1}+x^{(-1)/2}=6
The solution is x= 4/9