What is the answer to solvefor x,x^{1/2}+y^{1/2}=a^{1/2} ?

The answer to solvefor x,x^{1/2}+y^{1/2}=a^{1/2} is x=a-2a^{1/2}y^{1/2}+y

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solvefor x,x^{1/2}+y^{1/2}=a^{1/2}

solve for

x, x^{\frac{1}{2}} + y^{\frac{1}{2}} = a^{\frac{1}{2}}

x = a - 2 a^{\frac{1}{2}} y^{\frac{1}{2}} + y

Solution steps

x^{\frac{1}{2}} + y^{\frac{1}{2}} = a^{\frac{1}{2}}

Move

y^{\frac{1}{2}}

to the right side

x^{\frac{1}{2}} = a^{\frac{1}{2}} - y^{\frac{1}{2}}

Square both sides:

x = a - 2 a^{\frac{1}{2}} y^{\frac{1}{2}} + y

x = a - 2 a^{\frac{1}{2}} y^{\frac{1}{2}} + y

3^{3} x + 5 = 26

x^{2} - 2 2 x - 23 = 0

y^{2} = \frac{5}{2 \cdot lo g _{2} ( 16 ) + 5.4}

2 \cdot x^{2} - 4 3 x + 42 = 0

x + 6 = 121 - 36

What is the answer to solvefor x,x^{1/2}+y^{1/2}=a^{1/2} ?
The answer to solvefor x,x^{1/2}+y^{1/2}=a^{1/2} is x=a-2a^{1/2}y^{1/2}+y