What is the answer to x^2-sqrt(2x)+2=0 ?

The answer to x^2-sqrt(2x)+2=0 is No Solution for x\in\mathbb{R}

Solve for x: x^2-sqrt(2x)+2=0

The solution is No Solution for x\in\mathbb{R}

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x^{2} - 2 x + 2 = 0

No Solution for x \in R

Solution steps

x^{2} - 2 x + 2 = 0

Remove square roots

2 x = x^{4} + 4 x^{2} + 4

Solve

2 x = x^{4} + 4 x^{2} + 4 :

No Solution for

x \in R

No Solution for x \in R

\frac{( 2 x - 3 )}{( x - 1 )} = 2

0.8 = (\frac{1}{0.018}) [(1.63)]^{0.67} (s)^{\frac{1}{2}}

32 - x \cdot 15 = 27 + 5

x, r + s - 2 t = (2 x + y)^{\frac{1}{2}}

x + 4 + 3 = 5 x + 11

What is the answer to x^2-sqrt(2x)+2=0 ?
The answer to x^2-sqrt(2x)+2=0 is No Solution for x\in\mathbb{R}
Solve for x: x^2-sqrt(2x)+2=0
The solution is No Solution for x\in\mathbb{R}