What is the answer to 3/2+3/6+3/12+3/20 =n^{0.75} ?

The answer to 3/2+3/6+3/12+3/20 =n^{0.75} is n=\sqrt[3]{20736/625}

Solve for n: 3/2+3/6+3/12+3/20 =n^{0.75}

The solution is n=\sqrt[3]{20736/625}

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\frac{3}{2} + \frac{3}{6} + \frac{3}{12} + \frac{3}{20} = n^{0.75}

Solution steps

\frac{3}{2} + \frac{3}{6} + \frac{3}{12} + \frac{3}{20} = n^{0.75}

Take both sides of the equation to the power of

4 : \frac{20736}{625} = n^{3}

\frac{20736}{625} = n^{3}

Solve

Verify Solutions:

True

The solution is

x^{\frac{3}{2}} + 4 x^{- 1} - 5 x^{0} = 4

9 x^{2} - 6 x + 1 = 5

6 4 x^{2} = 8

\frac{3 x}{( x - 2 x + 9 )} = 0

x^{2} + 8 x + 16 = x + 4

What is the answer to 3/2+3/6+3/12+3/20 =n^{0.75} ?
The answer to 3/2+3/6+3/12+3/20 =n^{0.75} is n=\sqrt[3]{20736/625}
Solve for n: 3/2+3/6+3/12+3/20 =n^{0.75}
The solution is n=\sqrt[3]{20736/625}