What is the answer to 3/2+3/6+3/12+3/20 =n^{0.75} ?

The answer to 3/2+3/6+3/12+3/20 =n^{0.75} is n=\sqrt[3]{20736/625}

Solve for n: 3/2+3/6+3/12+3/20 =n^{0.75}

The solution is n=\sqrt[3]{20736/625}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{3}{2} + \frac{3}{6} + \frac{3}{12} + \frac{3}{20} = n^{0.75}

Decimal Notation

n = 3.21327 \dots

Solution steps

\frac{3}{2} + \frac{3}{6} + \frac{3}{12} + \frac{3}{20} = n^{0.75}

Take both sides of the equation to the power of

4 : \frac{20736}{625} = n^{3}

\frac{20736}{625} = n^{3}

Solve

Verify Solutions:

True

The solution is

x^{\frac{3}{2}} + 4 x^{- 1} - 5 x^{0} = 4

9 x^{2} - 6 x + 1 = 5

6 4 x^{2} = 8

\frac{3 x}{( x - 2 x + 9 )} = 0

x^{2} + 8 x + 16 = x + 4

What is the answer to 3/2+3/6+3/12+3/20 =n^{0.75} ?
The answer to 3/2+3/6+3/12+3/20 =n^{0.75} is n=\sqrt[3]{20736/625}
Solve for n: 3/2+3/6+3/12+3/20 =n^{0.75}
The solution is n=\sqrt[3]{20736/625}