What is the answer to sqrt(x^2-3x)=2 ?

The answer to sqrt(x^2-3x)=2 is x=4,x=-1

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sqrt(x^2-3x)=2

x^{2} - 3 x = 2

x = 4, x = - 1

Solution steps

x^{2} - 3 x = 2

Square both sides:

x^{2} - 3 x = 4

x^{2} - 3 x = 4

Solve

x^{2} - 3 x = 4 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions:

x = 4

True

, x = - 1

True

The solutions are

x = 4, x = - 1

x - 6 = x

\frac{x - 1}{x} + \frac{1 - 1}{x} = x

x^{2} + 2 x + 1 = x + 1

x - 2 x - 6 = 0

(x - 6)^{\frac{1}{2}} = 4