What is the answer to solvefor k,f=k^{1/3}*l^{1/2} ?

The answer to solvefor k,f=k^{1/3}*l^{1/2} is k=(f^3)/(l^{3/2)}

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solvefor k,f=k^{1/3}*l^{1/2}

solve for

k, f = k^{\frac{1}{3}} \cdot l^{\frac{1}{2}}

k = \frac{f ^{3}}{l ^{\frac{3}{2}}}

Solution steps

f = k^{\frac{1}{3}} l^{\frac{1}{2}}

Switch sides

k^{\frac{1}{3}} l^{\frac{1}{2}} = f

Divide both sides by

l^{\frac{1}{2}}

k^{\frac{1}{3}} = \frac{f}{l ^{\frac{1}{2}}}

Take both sides of the equation to the power of

3 : k = \frac{f ^{3}}{l ^{\frac{3}{2}}}

k = \frac{f ^{3}}{l ^{\frac{3}{2}}}

289 + x = \frac{( 1 )}{( 5 )}

(1 - x)^{\frac{3}{2}} = x

x + 5 - 10 = - 5

(x + 1)^{2} = ∣ - 5 ∣

5 x + 14 = x

What is the answer to solvefor k,f=k^{1/3}*l^{1/2} ?
The answer to solvefor k,f=k^{1/3}*l^{1/2} is k=(f^3)/(l^{3/2)}