What is the answer to sqrt(x^2-4)-x^2+4=0 ?

The answer to sqrt(x^2-4)-x^2+4=0 is x=sqrt(5),x=-sqrt(5),x=2,x=-2

Solve for x: sqrt(x^2-4)-x^2+4=0

The solution is x=sqrt(5),x=-sqrt(5),x=2,x=-2

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x^{2} - 4 - x^{2} + 4 = 0

x = 5, x = - 5, x = 2, x = - 2

Solution steps

x^{2} - 4 - x^{2} + 4 = 0

Remove square roots

x^{2} - 4 = x^{4} - 8 x^{2} + 16

Solve

x^{2} - 4 = x^{4} - 8 x^{2} + 16 : x = 5, x = - 5, x = 2, x = - 2

x = 5, x = - 5, x = 2, x = - 2

Verify Solutions:

x = 5

True

, x = - 5

True

, x = 2

True

, x = - 2

True

The solutions are

x = 5, x = - 5, x = 2, x = - 2

3 - x = 1

(2 x + 1)^{2} = \frac{1}{2}

\frac{3600}{12.96} = \frac{900}{12.96 - 2 a}

2 m + 1 = m + 1

x^{4} + x^{2} + 1 = x^{2} - 3 x + 1

What is the answer to sqrt(x^2-4)-x^2+4=0 ?
The answer to sqrt(x^2-4)-x^2+4=0 is x=sqrt(5),x=-sqrt(5),x=2,x=-2
Solve for x: sqrt(x^2-4)-x^2+4=0
The solution is x=sqrt(5),x=-sqrt(5),x=2,x=-2