What is the answer to |x^2-5x+2|=4 ?

The answer to |x^2-5x+2|=4 is x=(5-sqrt(33))/2 \lor x=2\lor x=3\lor x=(5+sqrt(33))/2

Solve for x: |x^2-5x+2|=4

The solution is x=(5-sqrt(33))/2 \lor x=2\lor x=3\lor x=(5+sqrt(33))/2

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x^{2} - 5 x + 2 = 4

x = \frac{5 - 33}{2} or x = 2 or x = 3 or x = \frac{5 + 33}{2}

Decimal Notation

x = - 0.37228 \dots, x = 2, x = 3, x = 5.37228 \dots

Solution steps

x^{2} - 5 x + 2 = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 5 x + 2 = - 4 or x^{2} - 5 x + 2 = 4

x^{2} - 5 x + 2 = - 4 or x^{2} - 5 x + 2 = 4

(x = 2 or x = 3) or (x = \frac{5 - 33}{2} or x = \frac{5 + 33}{2})

x = \frac{5 - 33}{2} or x = 2 or x = 3 or x = \frac{5 + 33}{2}

∣ x ∣ + ∣ x - 2 ∣ = 2

x^{2} - ∣ x ∣ - 2 = 0

x^{2} - x - 6 = x + 2

∣ x - 3 ∣ + ∣ 4 - x ∣ = 1

∣ x + 2 ∣ = 2 (3 - x)

What is the answer to |x^2-5x+2|=4 ?
The answer to |x^2-5x+2|=4 is x=(5-sqrt(33))/2 \lor x=2\lor x=3\lor x=(5+sqrt(33))/2
Solve for x: |x^2-5x+2|=4
The solution is x=(5-sqrt(33))/2 \lor x=2\lor x=3\lor x=(5+sqrt(33))/2