What is the answer to 2|x+1|^2-|x+1|=3 ?

The answer to 2|x+1|^2-|x+1|=3 is x=-5/2 \lor x= 1/2

Solve for x: 2|x+1|^2-|x+1|=3

The solution is x=-5/2 \lor x= 1/2

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2 ∣ x + 1 ∣^{2} - ∣ x + 1 ∣ = 3

x = - \frac{5}{2} or x = \frac{1}{2}

Decimal Notation

x = - 2.5, x = 0.5

Solution steps

2 ∣ x + 1 ∣^{2} - ∣ x + 1 ∣ = 3

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

x = - \frac{5}{2} or x = \frac{1}{2}

∣ x + 2 ∣ + ∣ x - 3 ∣ + 2 = 0

∣ x - 3 ∣ + 2 ∣ x + 1 ∣ = 4

2 \cdot (∣ x + 1 ∣^{2}) - ∣ x + 1 ∣ = 3

x^{2} - 4 x = 5

x^{2} + 4 x + 2 = \frac{( 5 x + 16 )}{3}

What is the answer to 2|x+1|^2-|x+1|=3 ?
The answer to 2|x+1|^2-|x+1|=3 is x=-5/2 \lor x= 1/2
Solve for x: 2|x+1|^2-|x+1|=3
The solution is x=-5/2 \lor x= 1/2